1341=16t^2

Solution for 1341=16t^2 equation:

1341=16t^2

We move all terms to the left:

1341-(16t^2)=0

a = -16; b = 0; c = +1341;
Δ = b2-4ac
Δ = 02-4·(-16)·1341
Δ = 85824
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{85824}=\sqrt{576*149}=\sqrt{576}*\sqrt{149}=24\sqrt{149}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{149}}{2*-16}=\frac{0-24\sqrt{149}}{-32}
=-\frac{24\sqrt{149}}{-32}
=-\frac{3\sqrt{149}}{-4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{149}}{2*-16}=\frac{0+24\sqrt{149}}{-32}
=\frac{24\sqrt{149}}{-32}
=\frac{3\sqrt{149}}{-4}
$